I was wondering how do get the current URI using JSTL and found this forum thread, JSTL EL for current page URL?.

If you want the actual URI of the JSP that is being rendered:

<c:out value="${pageContext.request.requestURI}"/>

If you want the original URI, which is probably the case, then:

<c:out value="${requestScope['javax.servlet.forward.request_uri']}"/>

In DSP if you want the original URI you can use the OriginatingRequest bean which implements the HttpServletRequest.

<dsp:valueof bean="/OriginatingRequest.requestURI" />